The H:C ratio in benzoic acid is <1, again suggesting the presence of several double bonds. On treatment with hot permanganate solution, cinnamaldehyde gave a stable, crystalline C 7H 6O 2 compound, now called benzoic acid. Surprisingly, products that appeared to retain many of the double bonds were obtained, and these compounds exhibited a high degree of chemical stability compared with known alkenes and cycloalkenes (aliphatic compounds). Since double bonds are easily cleaved by oxidative reagents such as potassium permanganate or ozone, and rapidly add bromine and chlorine, these reactions were applied to these aromatic compounds. Thursday, May 11,ġ1:30am NY 3:30pm London 9pm Mumbaiġ5 Common Mistakes in Applications\)īecause of the low hydrogen to carbon ratio in aromatic compounds (note that the H:C ratio in an alkane is >2), chemists expected their structural formulas would contain a large number of double or triple bonds. ✅ Subscribe to us on YouTube AND Get Forum Quiz FREE for 7 Days ✅ Find out which mistakes MBA applicants make most often and how to avoid these detrimental application errors. (Hexagon area) - (parallelogram area) = \((96\sqrt\) square cm Multiply by 2 for the area of the parallelogram, which = two of those trianglesĪrea of equilateral triangle* is a handy thing to know, s = side:Īrea of hexagon (six equilateral triangles):Īrea of parallelogram (two equilateral triangles) Multiply by 6 for the area of the hexagon. The other two angles of each triangle also = 60° both bisect a vertex of 120° = 60° eachįrom above: the six triangles are equilateral. Six sides of a hexagon divide 360° at center into six 60° angles at center There are 6 equilateral triangles.Īn equilateral triangle has three 60° angles. Unshaded region area = (hexagon area) - (parallelogram area)ĭividing shapes into triangles is an easy way to find area, especially when the polygons are regular (equal angles, equal sides).Ī regular polygon can be divided into congruent isosceles triangles.Ī regular hexagon is the only regular polygon that can be divided into congruent equilateral triangles.Ĭonnect the vertices. This prompt's wording and wordiness could confuse.
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